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Update thinkPHPBatchPoc.py #3

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@Scivous Scivous commented Aug 26, 2022

这个i=5判断有问题,如果i=4存在漏洞时,已经写入了i=i+1,所以当i=5时,就会生成no vulnerable告警,但flag已经变成了true,flag意义已经不存在了,所以应该设置flag为是否有漏洞的判断条件。

这个i=5判断有问题,如果i=4存在漏洞时,已经写入了i=i+1,所以当i=5时,就会生成no vulnerable告警,但flag已经变成了true,flag意义已经不存在了,所以应该设置flag为是否有漏洞的判断条件。
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