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Speed up OnDigraphs
for a digraph and a permutation
#267
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ChrisJefferson
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Original file line number | Diff line number | Diff line change |
---|---|---|
|
@@ -665,15 +665,19 @@ end); | |
InstallMethod(OnDigraphs, "for a mutable digraph by out-neighbours and a perm", | ||
[IsMutableDigraph and IsDigraphByOutNeighboursRep, IsPerm], | ||
function(D, p) | ||
local out; | ||
if ForAll(DigraphVertices(D), i -> i ^ p = i) then | ||
local out, permed; | ||
if p = () then | ||
return D; | ||
elif ForAny(DigraphVertices(D), i -> i ^ p > DigraphNrVertices(D)) then | ||
fi; | ||
|
||
out := D!.OutNeighbours; | ||
permed := Permuted(out, p); | ||
if Length(permed) > DigraphNrVertices(D) then | ||
Comment on lines
+674
to
+675
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. If |
||
ErrorNoReturn("the 2nd argument <p> must be a permutation that permutes ", | ||
"of the digraph <D> that is the 1st argument,"); | ||
fi; | ||
out := D!.OutNeighbours; | ||
out{DigraphVertices(D)} := Permuted(out, p); | ||
|
||
out{DigraphVertices(D)} := permed; | ||
Apply(out, x -> OnTuples(x, p)); | ||
ClearDigraphEdgeLabels(D); | ||
return D; | ||
|
@@ -682,7 +686,7 @@ end); | |
InstallMethod(OnDigraphs, "for a immutable digraph and a perm", | ||
[IsImmutableDigraph, IsPerm], | ||
function(D, p) | ||
if ForAll(DigraphVertices(D), i -> i ^ p = i) then | ||
if p = () then | ||
return D; | ||
fi; | ||
return MakeImmutable(OnDigraphs(DigraphMutableCopy(D), p)); | ||
|
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In one sense this is worse: previously we were testing whether
p
acts as the identity onDigraphVertices(D)
, which can be the case even ifp
is not the identity permutation. But I don't mind too much about losing that case.Is
p = ()
optimised somehow? Do all permutations inherently know whether or not they are the identity, for instance?There was a problem hiding this comment.
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P=() isn't specifically optimised, but it will almost always be very fast, espically if (as is common) the permutation moves the largest point it is defined on, as that is checked first.
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Just to say, we could use
SmallestMovedPoint
is we really care about saving this optimisation. That is still much faster than the old code, and would keep the same answer.