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solution(python): 746. Min Cost Climbing Stairs
746. Min Cost Climbing Stairs
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You are given an integer array cost where cost[i] is the cost of ith step on a staircase. Once you pay the cost, you can either climb one or two steps. | ||
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You can either start from the step with index 0, or the step with index 1. | ||
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Return the minimum cost to reach the top of the floor. | ||
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Example 1: | ||
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Input: cost = [10,15,20] | ||
Output: 15 | ||
Explanation: You will start at index 1. | ||
- Pay 15 and climb two steps to reach the top. | ||
The total cost is 15. | ||
Example 2: | ||
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Input: cost = [1,100,1,1,1,100,1,1,100,1] | ||
Output: 6 | ||
Explanation: You will start at index 0. | ||
- Pay 1 and climb two steps to reach index 2. | ||
- Pay 1 and climb two steps to reach index 4. | ||
- Pay 1 and climb two steps to reach index 6. | ||
- Pay 1 and climb one step to reach index 7. | ||
- Pay 1 and climb two steps to reach index 9. | ||
- Pay 1 and climb one step to reach the top. | ||
The total cost is 6. |
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class Solution(object): | ||
def minCostClimbingStairs(self, cost): | ||
n = len(cost) | ||
dp = [0] * (n + 1) | ||
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for i in range(2, n + 1): | ||
dp[i] = min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]) | ||
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return dp[n] |