Data

Fixes soyHenry#14

03 - Flujos de Control/mis_soluciones_homework_3.ipynb

@@ -0,0 +1,328 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": []
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "1) Crear una variable que contenga un elemento del conjunto de números enteros y luego imprimir por pantalla si es mayor o menor a cero"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "-10  El numero es menor que cero\n"
+     ]
+    }
+   ],
+   "source": [
+    "num = -10\n",
+    "if (num > 0):\n",
+    "    print(num,' El numero es mayor a cero')\n",
+    "elif (num < 0):\n",
+    "        print(num,' El numero es menor que cero')\n"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "2) Crear dos variables y un condicional que informe si son del mismo tipo de dato"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "No son del mismo tipo\n"
+     ]
+    }
+   ],
+   "source": [
+    "var1 = '4'\n",
+    "var2 = 2\n",
+    "if (type (var1) == type (var2)):\n",
+    "    print( var1, 'y', var2, ' son del mismo tipo')\n",
+    "else:\n",
+    "    print ('No son del mismo tipo')"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "3) Para los valores enteros del 1 al 20, imprimir por pantalla si es par o impar\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 10,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "1  Es impar\n",
+      "2  Es par\n",
+      "3  Es impar\n",
+      "4  Es par\n",
+      "5  Es impar\n",
+      "6  Es par\n",
+      "7  Es impar\n",
+      "8  Es par\n",
+      "9  Es impar\n",
+      "10  Es par\n",
+      "11  Es impar\n",
+      "12  Es par\n",
+      "13  Es impar\n",
+      "14  Es par\n",
+      "15  Es impar\n",
+      "16  Es par\n",
+      "17  Es impar\n",
+      "18  Es par\n",
+      "19  Es impar\n",
+      "20  Es par\n"
+     ]
+    }
+   ],
+   "source": [
+    "for n in range(1,21):\n",
+    "    if (n % 2 == 0):\n",
+    "        print (n, ' Es par')\n",
+    "    else:\n",
+    "        print(n, ' Es impar')"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "4) En un ciclo for mostrar para los valores entre 0 y 5 el resultado de elevarlo a la potencia igual a 3"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 12,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "0  Elevado a la 3 es  0\n",
+      "1  Elevado a la 3 es  1\n",
+      "2  Elevado a la 3 es  8\n",
+      "3  Elevado a la 3 es  27\n",
+      "4  Elevado a la 3 es  64\n",
+      "5  Elevado a la 3 es  125\n"
+     ]
+    }
+   ],
+   "source": [
+    "for n in range(0,6):\n",
+    "    print (n, ' Elevado a la 3 es ', (n ** 3))"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "5) Crear una variable que contenga un número entero y realizar un ciclo for la misma cantidad de ciclos"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 13,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "0\n",
+      "1\n",
+      "2\n",
+      "3\n",
+      "4\n",
+      "5\n",
+      "6\n",
+      "7\n",
+      "8\n",
+      "9\n"
+     ]
+    }
+   ],
+   "source": [
+    "var = 10\n",
+    "for var in range (var):\n",
+    "    print (var)\n",
+    "    var -= 1\n"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "6) Utilizar un ciclo while para realizar el factorial de un número guardado en una variable, sólo si la variable contiene un número entero mayor a 0"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "7) Crear un ciclo for dentro de un ciclo while"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 70,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "n=0\n",
+    "while (n > 3):\n",
+    "    n += 1\n",
+    "    for i in range (1,n):\n",
+    "        print (i,' ciclo For')\n",
+    "        print ('Ciclo while' , n)\n",
+    "    \n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "n = 0\n",
+    "while(n < 5):\n",
+    "    n += 1\n",
+    "    for i in range(1,n):\n",
+    "        print('Ciclo while nro ' + str(n))\n",
+    "        print('Ciclo for nro ' + str(i))"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "8) Crear un ciclo while dentro de un ciclo for"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 57,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "n = 5\n",
+    "for i in range (1,n):\n",
+    "    while (n < 5):\n",
+    "        n -= 1\n",
+    "        print('Ciclo ', n)"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 56,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "n = 5\n",
+    "for i in range(1, n):\n",
+    "    while(n < 5):\n",
+    "        n -= 1\n",
+    "        print('Ciclo while nro ' + str(n))\n",
+    "        print('Ciclo for nro ' + str(i))"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "9) Imprimir los números primos existentes entre 0 y 30"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "10) ¿Se puede mejorar el proceso del punto 9? Utilizar las sentencias break y/ó continue para tal fin"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.11.1"
+  },
+  "orig_nbformat": 4,
+  "vscode": {
+   "interpreter": {
+    "hash": "89a5003fa4d04edff07a126a2c6f2ee59ee1adb31e9fcd60b29f2b77c18232ea"
+   }
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 2
+}