Andres Ballares #172
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Andres Ballares #172
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| newArray.push(array[i] + "!"); | ||
| } | ||
| return newArray; | ||
| } |
problems/arraysWithLoops.js
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| /** | ||
| * Takes in array and returns the smallest number in the array | ||
| * @param {number[]} nums | ||
| * @returns {number} smallest value | ||
| */ | ||
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| function findSmallest() {} | ||
| function findSmallest(nums) { | ||
| let i = 0; |
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We don't need this i here b/c we're declaring an i with our for loop.
| function findSecondLargest(nums) { | ||
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| let largest = Infinity; | ||
| let secondLargest = Infinity; |
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If we start at Infinity and are looking for the largest number, Infinity will always win. What's the smallest number in the world that we can start with?
| i++; | ||
| } else { | ||
| arr.push(i + " is odd"); | ||
| i++; |
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we can move i++ outside / after the if else b/c it should increment regardless.
| newArray.push(sum); | ||
| } | ||
| return newArray; | ||
| }; |
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