Completed HW Assignment - Emily #6
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| const playerDifference = 21 - playerCardScore | ||
| const dealerDifference = 21 - dealerCardScore | ||
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| if (playerCardScore > 21 && dealerCardScore > 21) { |
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@kcycle nice job, good use of if..else if to cover all the necessary conditions. Take a look at the solution to view an alternative if..else structure for this problem: https://github.com/jsd20191008/hw-01-functions-solution/blob/master/pset-functions.js#L33
| function wordCount (phrase) { | ||
| const countArray = { } | ||
| for (let i = 0; i < phrase.length; i++) { | ||
| countArray[ phrase[i] ] = (countArray[phrase[i]] || 0) +1 |
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@kcycle nice use of bracket notation to build out your wordcount object
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| function wordCount (phrase) { | ||
| const countArray = { } |
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@kcycle the name chosen for this variable is a little confusing since the actual datatype you're creating is an object and not an array
| @@ -136,6 +191,48 @@ console.log('Problem 3:') | |||
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| // Add your code below this line | |||
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| const word = "javascript" | |||
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| const scoreKey = { | |||
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@kcycle nice job using an object to map letters to their respective scores
| const wordSplit = word.split('') | ||
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| const scoreArray = wordSplit.map(letter => scoreKey[letter]) | ||
| const totalScore = scoreArray.reduce((a,b) => a + b) |
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@kcycle impressive use of .map() and .reduce() to calculate the total score associated with each word
| @@ -208,6 +319,24 @@ console.log('Problem 5:') | |||
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| // Add your code below this line | |||
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| const wordy = 'rune' | |||
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| function doubleLetters(word) { | |||
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@kcycle great approach, Using a variable to represent the "last letter" make your solution easy to navigate. Also, great use of a return statement to exit out of the function as soon as a match is found
| const testWord = 'run' | ||
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| function isPalindrome (testWord) { | ||
| return testWord === testWord.split('').reverse().join(''); |
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@kcycle great job! |
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