Solution #2187
Solution #2187
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Great job on implementing the formatDate function! 🎉 It meets the task requirements and handles the conversion between date formats effectively. While there are a few areas for improvement, such as clarifying the handling of the 'YY' format and ensuring robust handling of input cases, these do not significantly impact the core functionality. Keep up the good work, and consider the feedback for future enhancements! 😊
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| if (dateNumbers[i] < 30) { | ||
| dateObj.year = `20${dateNumbers[i]}`; | ||
| } else { | ||
| dateObj.year = `19${dateNumbers[i]}`; |
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The logic for determining the century for 'YY' format assumes that any year less than 30 belongs to the 2000s, and any year 30 or greater belongs to the 1900s. This is a common heuristic but may not be universally applicable. Consider making this logic configurable or document this assumption clearly.
| const fromFormatArray = [aFrom, bFrom, cFrom]; | ||
| const [aTo, bTo, cTo, newSeparator] = toFormat; | ||
| const toFormatArray = [aTo, bTo, cTo]; | ||
| const dateinNumbers = date.split(separator); |
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Ensure that the date string contains the expected number of segments when split by separator. If the date string does not match the expected format, this could lead to unexpected behavior or errors.
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| const dateInfo = getDateFromOld(fromFormatArray, dateinNumbers); | ||
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| return setDateOrderNew(toFormatArray, dateInfo).join(newSeparator); |
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The setDateOrderNew function assumes that dateInfo contains all necessary date parts. Ensure that getDateFromOld correctly populates dateInfo with all required fields, or handle cases where some fields might be missing.
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