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Solution #1594
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Solution #1594
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Original file line number | Diff line number | Diff line change |
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class Person: | ||
# write your code here | ||
pass | ||
people = {} | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Issue: Using names as keys in the Suggestion: Consider using a unique identifier for each person or implement a strategy to handle potential name collisions. |
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def __init__(self, name: str, age: int) -> None: | ||
self.name = name | ||
self.age = age | ||
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def create_person_list(people: list) -> list: | ||
# write your code here | ||
pass | ||
Person.people[name] = self | ||
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def create_person_list(people: list[dict]) -> list: | ||
person_list = [] | ||
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for person_data in people: | ||
person = Person(name=person_data.get("name"), | ||
age=person_data.get("age")) | ||
person_list.append(person) | ||
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for person_data in people: | ||
person = Person.people[person_data.get("name")] | ||
if "wife" in person_data and person_data.get("wife"): | ||
person.wife = Person.people[person_data.get("wife")] | ||
if "husband" in person_data and person_data.get("husband"): | ||
person.husband = Person.people[person_data.get("husband")] | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. The code assumes that the 'wife' and 'husband' keys, if present, will always have valid corresponding entries in the |
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return person_list |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Using a class variable
people
to store instances by name can lead to issues if names are not unique. Consider using a unique identifier or handling potential name collisions.