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Solution #1643

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Solution #1643

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7377f7e
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rpk6432 Dec 18, 2024
87afc85
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rpk6432 Dec 19, 2024
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27 changes: 23 additions & 4 deletions app/main.py
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Original file line number Diff line number Diff line change
@@ -1,8 +1,27 @@
class Person:
# write your code here
pass
people = {}
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Using a dictionary with names as keys (Person.people) can lead to issues if two people have the same name, as one entry will overwrite the other. Consider using unique identifiers for each person.

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Using a class-level dictionary Person.people can lead to issues if multiple instances are created or if the function is called multiple times. Consider using instance-level storage or ensuring unique keys.


def __init__(self, name: str, age: int) -> None:
self.name = name
self.age = age
Person.people[name] = self
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Using name as a key in Person.people can cause overwriting if two people have the same name. Consider using a unique identifier for each person.



def create_person_list(people: list) -> list:
# write your code here
pass
Person.people = {}

for person in people:
name, age = person["name"], person["age"]
Person(name, age)

for person in people:
name = person["name"]
if "wife" in person and person["wife"]:
Person.people[name].wife = Person.people[person["wife"]]
Person.people[person["wife"]].husband = Person.people[name]
Comment on lines +19 to +21
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Ensure that person['wife'] exists in Person.people before attempting to access it. This will prevent potential KeyError exceptions.


if "husband" in person and person["husband"]:
Person.people[name].husband = Person.people[person["husband"]]
Person.people[person["husband"]].wife = Person.people[name]
Comment on lines +23 to +25
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Ensure that person['husband'] exists in Person.people before attempting to access it. This will prevent potential KeyError exceptions.


return list(Person.people.values())
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