Develop #673
Develop #673
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Great job on implementing the solution! 🎉 The code meets the task requirements and is well-structured across multiple modules. While there are a few minor issues to address, such as handling cases where a product is not available and ensuring the customer can afford the trip even with exact funds, these do not significantly impact the overall functionality. Keep up the good work and consider these improvements for future projects! 😊
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| def calculate_distance(home: list, shop: list) -> float: | ||
| return math.sqrt((shop[0] - home[0]) ** 2 + (shop[1] - home[1]) ** 2) |
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The calculate_distance method assumes that both home and shop lists have exactly two elements (representing x and y coordinates). It would be safer to validate the length of these lists before performing calculations to avoid potential index errors.
| def total_cost(self, shop: Shop, fuel_price: float) -> float: | ||
| distance = self.car.calculate_distance(self.location, shop.location) | ||
| fuel_cost = self.car.fuel_cost(distance * 2, fuel_price) | ||
| product_cost = shop.products_cost(self.client_products) |
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The products_cost method in the Shop class returns -1 if a product is not available. You should handle this case in the total_cost method to avoid incorrect calculations.
| if 0 < total_cost < best_cost: | ||
| best_cost = total_cost | ||
| best_shop = shop | ||
| if self.money > best_cost: |
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The condition if self.money > best_cost should be if self.money >= best_cost to ensure the customer can afford the trip even if they have exactly the amount needed.
| if product_name in self.products: | ||
| total += self.products[product_name] * amount | ||
| else: | ||
| return -1 |
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Returning -1 when a product is not available is a valid approach, but ensure that the calling code handles this case to avoid incorrect calculations or logic errors.
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