crud

.gitignore

@@ -0,0 +1 @@
+node_modules

index.js

@@ -0,0 +1,87 @@
+const express = require('express')
+const methodOverride = require('method-override');
+const mongoose = require('mongoose');
+const path = require('path');
+const Campground = require('./models/campground'); //引用的语法是这样的，要用哪个文件，把它引用进来
+
+
+const app = express()
+
+mongoose.connect('mongodb://localhost:27017/test1'), {
+    useNewUrlParser: true,
+    useCreateIndex: true,
+    useUnifiedTopology: true //没太弄懂是干什么的配置，老师也没怎么讲。但是如果不装的话就会有警告
+};
+
+const db = mongoose.connection;
+db.on("error", console.error.bind(console, "connection error:"));
+db.once("open", () => {
+    console.log("Database connected");
+});
+
+app.set('view engine', 'ejs')
+app.set('views', path.join(__dirname, 'views'))
+//原本在哪个路径下运行，就会去那个路径的view里面找，但这个让找的路径固定到当前文件路径+views下
+app.use(express.json()) // for parsing application/json
+app.use(express.urlencoded({ extended: true })) // for parsing the body, 如何知道这些具体的配置？
+app.use(methodOverride('_method')); //这里是设定了需要overide的变量名，传入url的里面哪一个overide了method
+
+
+app.get('/', (req, res) => {
+    res.render('home')
+});
+
+app.get('/campgrounds', async (req, res) => {
+    const campgrounds = await Campground.find({});
+    res.render('campgrounds/index', { campgrounds });
+})
+
+app.get('/campgrounds/new', (req, res) => {
+    res.render('campgrounds/new');
+})
+
+//他也不是一步做出来的，先写死了一个campground的结构体，测试一下保存再render，而且在db里面看了是否保存上了，可以的话再进行下一步
+//？？？因为http请求方法不同，可以共用一个url，但是为什么不加new或者什么的，就直接post呢？
+app.post('/campgrounds', async (req, res) => {
+    const campground = new Campground(req.body.campground);
+    //这里之所以出了好多问题，是因为没有理解，get的参数是放在param里的，而post是放在body里的！！
+    await campground.save();
+    res.redirect(`/campgrounds/${campground._id}`);
+    //???下划线是什么意思,如何知道是get？
+})
+
+app.get('/campgrounds/:id', async (req, res) => {
+    const campground = await Campground.findById(req.params.id);
+    res.render('campgrounds/show', { campground });
+})
+
+app.get('/campgrounds/:id/edit', async (req, res) => {
+    const campground = await Campground.findById(req.params.id);
+    res.render('campgrounds/edit', { campground })
+})
+
+app.put('/campgrounds/:id', async (req, res) => {
+    const { id } = req.params
+    const campground = await Campground.findByIdAndUpdate(id, { ...req.body.campground });
+    // ... spread the object in the body to the new object
+    res.redirect(`/campgrounds/${campground._id}`)
+})
+
+app.delete('/campgrounds/:id', async (req, res) => {
+    const { id } = req.params;
+    console.log(`delete campground id ${id}`)
+    await Campground.findByIdAndDelete(id);
+    res.redirect('/campgrounds');
+})
+
+
+
+
+//todo 如果不是主页面进去的，链接进去的，也要加路径吗？似乎是要的？这里规定了每条
+//路径走到哪个页面，然后原本的页面只能进入那个页面的一个入口
+
+
+
+app.listen(3000, () => {
+    console.log(`Serving listening at http://localhost:3000`)
+})

models/campground.js

@@ -0,0 +1,12 @@
+const mongoose = require('mongoose');
+const Schema = mongoose.Schema;
+
+const CampgroundSchema = Schema({
+    title: String,
+    price: String,
+    description: String,
+    location: String
+});
+
+module.exports = mongoose.model('Campground', CampgroundSchema);
+