Correctly extracting class path from maven output

usethesource · Aug 27, 2024 · 718a6b3 · 718a6b3
1 parent d5c655b
commit 718a6b3
Showing 1 changed file with 2 additions and 8 deletions.
diff --git a/src/org/rascalmpl/library/util/PathConfig.java b/src/org/rascalmpl/library/util/PathConfig.java
@@ -634,10 +634,6 @@ private static ISourceLocation setTargetScheme(ISourceLocation projectLoc) {
         }
     }
 
-
-    private static final Pattern FIND_CLASS_PATH = Pattern.compile("org.apache.maven.plugins.dependency.fromDependencies.BuildClasspathMojo - Dependencies classpath:\\s+(.+)$", Pattern.MULTILINE);
-
-
     /**
      * See if there is a pom.xml and extract the compile-time classpath from a mvn run
      * if there is such a file.
@@ -663,11 +659,9 @@ private static IList getPomXmlCompilerClasspath(ISourceLocation manifestRoot) {
 
             maven.doMain(buildRequest(new String[] {"-o", "dependency:build-classpath", "-DincludeScope=compile", "-Dmdep.outputFile=" + tempFile.toString()}, manifestRoot));
 
-            var mavenOutput = Files.readAllLines(tempFile);
-            var match = FIND_CLASS_PATH.matcher(mavenOutput.get(0));
-            var foundClassPath = match.find() ? match.group(1) : "";
+            var foundClassPath = Files.readAllLines(tempFile);
 
-            return Arrays.stream(foundClassPath.split(File.pathSeparator))
+            return Arrays.stream(foundClassPath.get(0).split(File.pathSeparator))
                 .filter(fileName -> new File(fileName).exists())
                 .map(elem -> {
                     try {